IIFT 2018 Question 98

Question 98

In the triangle PQR, S is the midpoint of QR. X is any point on PR. T is the point on QR such that PT || SX. If the area of triangle PQR is 5.8 sq. cm. then the area of triangle RTX is


S is the midpoint of QR. So, area of PSR = $$\frac{1}{2}\left(Area\ of\ PQR\right)\ =\ \frac{5.8}{2}=2.9$$


So area of XSP = area of XST ( same height and same base)

Adding area of XSR on both sides, we have area of PSR = Area of RTX

=>  area of PSR = Area of RTX = 2.9 sq.cm

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2 years, 2 months ago

solution kha sir ji ..

Kalpna Manral

2 years, 4 months ago

Please give full solution of this question

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