Question 98
In the triangle PQR, S is the midpoint of QR. X is any point on PR. T is the point on QR such that PT || SX. If the area of triangle PQR is 5.8 sq. cm. then the area of triangle RTX is
Solution
S is the midpoint of QR. So, area of PSR = $$\frac{1}{2}\left(Area\ of\ PQR\right)\ =\ \frac{5.8}{2}=2.9$$
PT||XS
So area of XSP = area of XST ( same height and same base)
Adding area of XSR on both sides, we have area of PSR = Area of RTX
=> area of PSR = Area of RTX = 2.9 sq.cm
Video Solution
Create a FREE account and get:
- All Quant Formulas and shortcuts PDF
- 40+ previous papers with solutions PDF
- Top 500 MBA exam Solved Questions for Free
CAT Quant Questions | CAT Quantitative Ability
CAT Number Systems QuestionsCAT Remainders QuestionsCAT Progressions and Series QuestionsCAT Profit And Loss QuestionsCAT Arithmetic Questions
CAT DILR Questions | LRDI Questions For CAT
CAT Data change over a period QuestionsCAT Charts QuestionsCAT Games and Tournamnents QuestionsCAT DI with connected data sets QuestionsCAT Truth Lie Concept Questions
