Question 98

The interior angle of a regular polygon exceedsits extenior angle by $$108^\circ$$, The numberof sides ofthe polygonis

Solution

.

Let the exterior angle be x

given , the interior angle of a regular polygon exceeds its exterior angle by 108degree.

So, interior angle = x+108

as, the sum of interior angle and exterior angle = 180°

So,

Hence , polygon has 10 sides

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