In $$\triangle ABC, \angle A = 66^\circ$$ and $$\angle B = 50^\circ$$. If the bisectors of $$\angle B$$ and $$\angle C$$ meet at P, then $$\angle BPC - \angle PCA = ?$$

A

$$93^\circ$$

B

$$91^\circ$$

C

$$83^\circ$$

D

$$81^\circ$$