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Solution
Expression :Â $$((3^4)^2 \times \frac{1}{27^2})^2 + 9$$ = ?
= $$[(3)^8\times(3)^{-6}]^2+9$$
= $$[(3)^{8-6}]^2+9$$
= $$3^4+9=90$$
=> Ans - (D)
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