RPF 10 Jan 2019

Question 96

Simplify:
$$((3^4)^2 \times \frac{1}{27^2})^2 + 9$$ = ?

Solution

Expression : $$((3^4)^2 \times \frac{1}{27^2})^2 + 9$$ = ?

= $$[(3)^8\times(3)^{-6}]^2+9$$

= $$[(3)^{8-6}]^2+9$$

= $$3^4+9=90$$

=> Ans - (D)


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