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Solution
Expression : $$tan(2A)$$
$$\because tan(A+B)=\frac{tanA+tanB}{1-tanAtanB}$$
Replacing B by A
=> $$tan(A+A)=\frac{tanA+tanA}{1-tanAtanA}$$
=> $$tan(2A)=\frac{2tanA}{1-tan^2A}$$
=> Ans - (A)
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