Question 95
If parties D, E and F form a coalition they would be still short of how many seats to reach the half way mark?
Solution
Total number of seats = 100 + 15 + 25 + 40 + 60 + 90 + 70 = 400
Number of seats of parties D, E and F = 40 + 60 + 90 = 190
Number of seat required to reach the half way mark $$(\frac{400}{2}=200)$$ is = $$200-190=10$$
=> Ans - (C)
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