Base of a right pyramid is a square of side 10cm. If the height of the pyramid is 12cm, then its total surface area is
Area of base =10×10=100cm^2
Area of 4 Phase
=(12×Base×slant height)×4
(12×10×13)×4 ...............[Slant height = √(122+52)=√169=13]
=(64×4)=260
Total Surface area
260+100
360cm^2
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