Question 95

Base of a right pyramid is a square of side 10cm. If the height of the pyramid is 12cm, then its total surface area is

Solution

Area of base =10×10=100cm^2

Area of 4 Phase

=(12×Base×slant height)×4

(12×10×13)×4 ...............[Slant height = (122+52)=√169=13]

=(64×4)=260

Total Surface area

260+100

360cm^2


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