Question 94

What is the value of √2 Sec 45° + (1/√3)Tan 30°?

Solution

Expression : √2 Sec 45° + (1/√3)Tan 30°

= $$(\sqrt2 \times \sqrt2)+(\frac{1}{\sqrt3} \times \frac{1}{\sqrt3})$$

= $$2+\frac{1}{3}=\frac{7}{3}$$

=> Ans - (C)

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