Solution
$$\frac{sin2A}{1+cos2A}=\frac{2sinAcosA}{2cos^{2}A}=tanA$$
so the answer is option A.
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$$\frac{sin2A}{1+cos2A}=\frac{2sinAcosA}{2cos^{2}A}=tanA$$
so the answer is option A.
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