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Equation 1 : 4x - 3y = 10
Equation 2 : 3x + y = 14
Multiplying equation (ii) by 3 and adding it to equation (i)
=> $$(4x+9x)+(-3y+3y)=(10+42)$$
=> $$13x=52$$
=> $$x = \frac{52}{13}=4$$
Substituting it in equation (ii), => $$y=14-3(4) = 14 - 12 = 2$$
$$\therefore (x,y)=(4,2)$$
=> Ans - (B)
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