Question 92

What is the equation of the line perpendicular to the line 5x + 3y = 6 and having Y-intercept -3?

Solution

slope = m = -a/b = -5/3, c = -3

eq of perpendicular line is

y = (-1/m)x + c

y = (3/5)x - 3

5y = 3x - 15

3x - 5y = 15

so the answer is option A.

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