The diameter of a circle is equal to the side of the square. What is the area of the square if the area of the circle is 64π sq cm?
Let radius of circle = $$r$$ cm
Area of circle = $$\pi r^2 = 64 \pi$$
=> $$r^2 = 64$$
=> $$r = \sqrt{64} = 8$$ cm
Thus, diameter of circle = Side of square = $$2 \times 8 = 16$$ cm
$$\therefore$$ Area of square = $$(16)^2 = 256 cm^2$$
=> Ans - (D)
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