Question 92

In the given figure, AP = 3 cm, AR = 6 cm and RS = 9 cm, then what is the value (in cm) of PQ?

Solution

In the above figure, $$(AP)\times(AQ)=(AR)\times(AS)$$

Let PQ = $$x$$ cm

=> $$(3)\times(3+x)=(6)\times(6+9)$$

=> $$x+3=\frac{6}{3}\times15$$

=> $$x+3=2\times15=30$$

=> $$x=30-3=27$$

=> Ans - (D)

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