Three fractions x, y and z are such rhat x > y > z. When the smallest of them is divided by the greatest, the result is $$\frac{9}{16}$$, which exceeds y by 0.0625 . If  x+y+z=$$2\frac{3}{12}$$, then what is the value of x+z?

A

$$\frac{5}{4}$$

B

$$\frac{3}{4}$$

C

$$\frac{7}{4}$$

D

$$\frac{1}{4}$$