Solution
Let AD = 5 and DB = 3
DE $$\parallel$$ BC and thus $$\triangle$$ ADE $$\sim$$ $$\triangle$$ ABC
=> $$\frac{AD}{DE}=\frac{AB}{BC}$$
=> $$\frac{DE}{BC}=\frac{AD}{AD+DB}$$
=> $$\frac{DE}{BC}=\frac{5}{5+3}$$
=> $$\frac{DE}{BC}=\frac{5}{8}$$
=> Ans - (A)
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