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Question 90
In ΔABC, ∠BAC = 90° and AD is drawn perpendicular to BC. If BD = 7 cm and CD = 28 cm, then what is the length (in cm) of AD?
Solution
Given : BD = 7 cm and DC = 28 cm
To find : AD = ?
Solution : In $$\triangle$$ ABC
=> $$(AD)^2=(BD)\times(DC)$$
=> $$(AD)^2=7\times28=196$$
=> $$AD=\sqrt{196}=14$$ cm
=> Ans - (D)
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