Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 91
A chord of length 60 cm is at a distance of 16 cm from the centre of a circle. What is the radius (in cm) of the circle?
Solution
Given : AB = 60 cm and OC = 16 cm
To find : OB = $$r$$ = ?
Solution : The line from the centre of the circle to the chord bisects it at right angle.
=> AC = BC = $$\frac{1}{2}$$ AB
=> BC = $$\frac{60}{2}=30$$ cm
In $$\triangle$$ OBC,
=> $$(OB)^2=(BC)^2+(OC)^2$$
=> $$(OB)^2=(30)^2+(16)^2$$
=> $$(OB)^2=900+256=1156$$
=> $$OB=\sqrt{1156}=34$$ cm
=> Ans - (B)
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
