Find the sum of the measures all the interior angles of a polygon having 12 sides.
Sum of all interior angles of a polygon having $$n$$ sides = $$(n - 2) \times 180$$°
Number of sides of polygon, $$n = 12$$
=> Sum of interior angles = $$(12 - 2) \times 180$$°
= $$10 \times 180 = 1800$$°
=> Ans - (A)
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