Masses $$m_1$$ and $$m_2$$ are connected to a string passing over a pulley as shown. Mass $$m_1$$ starts from rest and falls through a distance $$d$$ in time $$t$$. Now, by interchanging the masses the time required for $$m_2$$ to fall through the same distance is $$2t$$. Therefore, the ratio of masses $$m_1 \colon m_2$$ is

A

$$\frac{2}{3}$$

B

$$\frac{3}{2}$$

C

$$\frac{5}{2}$$

D

$$\frac{4}{3}$$