A contractor constructed a big hall, rectangular in shape, with length 32 meters and breadth 18 meters. He wanted to buy 1 meter by 1 meter tiles. But in the shop 3 meter by 2 meter tiles only were available. How many tiles he has to buy for tiling the floor?

Solution

Each 3 m by 2 m tile covers the same area as $$3 \times 2 = 6$$ of the 1 m by 1 m tiles. The number of 3 m by 2 m tiles needed is $$\frac{32}{2} \times \frac{18}{3} = 16 \times 6 = 96$$.

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