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Question 8

A square of side 3 cm is cut into 9 equal squares. Another square of side 4 cm is cut into 16 equal squares. Saket made a bigger square using all the smaller square bits. The length of the side of the bigger square is (in cm)

The 9 unit squares from the first square and the 16 unit squares from the second square together give $$9 + 16 = 25$$ unit squares of area 1 sq cm each. Since $$25 = 5^2$$, these can be arranged into one bigger square of side $$5$$ cm.

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