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Question 7

A is the smallest three digit number which leaves a remainder 2 when divided by 17. B is the smallest three digit number which leaves a remainder 7 when divided by 12. Then $$A + B$$ is

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The smallest three digit number leaving remainder 2 on division by 17 is $$A = 104$$, since $$17 \times 6 + 2 = 104$$. The smallest three digit number leaving remainder 7 on division by 12 is $$B = 103$$, since $$12 \times 8 + 7 = 103$$. So $$A + B = 104 + 103 = 207$$.

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