If Q(0, -1, -3) is the image of the point P in the plane $$3x - y + 4z = 2$$ and R is the point (3, -1, -2), then the area (in sq. units) of $$\triangle PQR$$ is

A

$$\frac{\sqrt{91}}{4}$$

B

$$\frac{\sqrt{91}}{2}$$

C

$$2\sqrt{13}$$

D

$$\frac{\sqrt{65}}{2}$$