-(1 + sec $$20^\circ$$ + cot $$70^\circ$$)(1 - cosec $$20^\circ$$ + tan$$70^\circ$$) is equal to
(1 + sec $$20^\circ$$ + cot $$70^\circ$$)(1 - cosec $$20^\circ$$ + tan$$70^\circ$$)
=Â (1 + sec $$20^\circ$$ + tan $$20^\circ$$)(1 - cosec $$20^\circ$$ + cot$$20^\circ$$)
= (1 +Â $$\frac{1}{cos20^\circ}$$ + $$\frac{sin20^\circ}{cos20^\circ}$$)(1 - $$\frac{1}{sin20^\circ}$$ + $$\frac{cos20^\circ}{sin20^\circ}$$)
= ($$\frac{1+cos20^\circ+sin20^\circ}{cos20^\circ}$$)($$\frac{sin20^\circ-1+cos20^\circ}{sin20^\circ}$$)
=  $$\frac{(cos20^\circ+sin20^\circ)^2-1}{cos20^\circ sin20^\circ}$$
= $$\frac{2cos20^\circ sin20^\circ}{cos20^\circ sin20^\circ}$$
=2
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