If $$a^{2}sec^{2} x-b^{2} tan^{2} x$$=$$c^{2}$$ then the value of $$sec^{2} x+tan^{2} x $$ is equal to ($$ b^{2} \neq  a^{2}$$)

A

$$\frac{b^{2}-a^{2}+2C^{2}}{b^{2}+a^{2}}$$

B

$$\frac{b^{2}+a^{2}-2C^{2}}{b^{2}-a^{2}}$$

C

$$\frac{b^{2}-a^{2}-2C^{2}}{b^{2}+a^{2}}$$

D

$$\frac{b^{2}-a^{2}}{b^{2}+a^{2}+2 C^{2}}$$