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Let the fraction be $$x$$
According to ques,
=> $$x+\frac{4}{x}=5$$
=> $$\frac{x^2+4}{x}=5$$
=> $$x^2+4=5x$$
=> $$x^2-5x+4=0$$
=> $$x^2-x-4x+4=0$$
=> $$x(x-1)-4(x-1)=0$$
=> $$(x-1)(x-4)=0$$
=> $$x=1,4$$
=> Ans - (A)
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