In $$\triangle ABC, \angle A = 58^\circ$$. If I is the in center of the triangle, then the measure of $$\angle BIC$$ is:
$$\angle BIC = 90\degree +Â \angle A/2$$
$$\angle BIC = 90\degree + 58/2 =Â 90\degree + 29\degree = 119\degree$$
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