Question 87

In $$\triangle ABC, \angle A = 58^\circ$$. If I is the in center of the triangle, then the measure of $$\angle BIC$$ is:

Solution

$$\angle BIC = 90\degree + \angle A/2$$
$$\angle BIC = 90\degree + 58/2 = 90\degree + 29\degree = 119\degree$$


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