Question 87

If 1/√(1+$$tan^{2}$$A) = x, then value of x is

Solution

Expression : 1/√(1+$$tan^{2}$$A) = x

$$\because (sec^2A-tan^2A=1)$$

= $$\frac{1}{\sqrt{sec^2A}}$$

= $$\frac{1}{secA} = cosA$$

=> Ans - (A)

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