An engineering student has to secure 25% marks to pass. He gets 45 and fails by 45 marks. Find the maximum marks.
Let maximum marks = $$100x$$
=> Passing marks = $$\frac{25}{100} \times 100x = 25x$$
According to ques,Â
=> $$25x - 45 = 45$$
=> $$25x = 45 + 45 = 90$$
=> $$x = \frac{90}{25} = \frac{18}{5}$$
$$\therefore$$ Maximum marks = $$100 \times \frac{18}{5} = 360$$
=> Ans - (D)
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