A thief is stopped by a policeman from a distance of 450 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 7 km/h and that of policeman as 12 km/h, how far the thief would have run, before he is overtaken?
Since the thief is escaping from the police man, thus they both are running in same direction.
Speed of thief = 7 km/hr and speed of policeman = 12 km/hr
=> Relative speed = 12 - 7 = 5 km/hr
Distance between them = 450 metres = 0.45 km
=> Time taken = $$\frac{distance}{speed}$$
= $$\frac{0.45}{5} = \frac{9}{100}$$ hr
$$\therefore$$ Distance covered by thief before he was caught = $$7 \times \frac{9}{100}$$
= 0.63 km = 630 metres
=> Ans - (D)
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