A thief is stopped by a policeman from a distance of 450 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 7 km/h and that of policeman as 12 km/h, how far the thief would have run, before he is over­taken?

Since the thief is escaping from the police man, thus they both are running in same direction.

Speed of thief = 7 km/hr and speed of policeman = 12 km/hr

=> Relative speed = 12 - 7 = 5 km/hr

Distance between them = 450 metres = 0.45 km

=> Time taken = $$\frac{distance}{speed}$$

= $$\frac{0.45}{5} = \frac{9}{100}$$ hr

$$\therefore$$ Distance covered by thief before he was caught = $$7 \times \frac{9}{100}$$

= 0.63 km = 630 metres

=> Ans - (D)