Join WhatsApp Icon CAT WhatsApp Group
Question 84

The smallest positive integer, when increased by 9, is exactly divisible by 3, 4, 10, 15, 24 is

The LCM of 3, 4, 10, 15 and 24

LCM= 120

Hence ,the smallest positive integer is 120.

Hence the required integer is $$=120-9=111$$

Create a FREE account and get:

  • Download Maths Shortcuts PDF
  • Get 300+ previous papers with solutions PDF
  • 500+ Online Tests for Free