Question 83

The number of divisors excluding 1 and itself of the number 8625 is

Solution

As per the given question,

$$ 8625 =3\times 5\times 5\times 5\times 23$$

$$8625=3^1\times 5^3\times 23^1$$

Hence the number of divisors $$=(3+1)(1+1)(1+1)=4\times 2 \times 2=16$$

After excluding 1, the number of divisors $$16-2=14$$

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