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Question 84
In the diagram given below, $$\angle{ABD}$$ = $$\angle{CDB}$$ = $$\angle{PQD}$$ = 90° . If AB:CD = 3:1, the ratio of CD: PQ is
Solution
Let BQ = z , QD = y , PQ = x.
From similar triangles PQD and ABD we have
(y/x) = (z+y)/3 .
Also from similar triangles PQB and CBD we have
(z/x) = z+y .
Solving we get z = 3*y.
Now required ratio is (z+y)/z.
We get eual to 4/3 which is equal to 1:0.75.
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