Question 84

For the cumulative distribution function 

$$F(x) = \begin{cases}0; & x < -1\\\frac{1}{2}(x + 1)^2; & -1 \leq x \leq 0 \\1-\frac{(1-x)^2}{2}; & 0 \leq x \leq 1\\1; & 1 < x < \infty \end{cases}$$

the upper quartile point is


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