A circle is inscribed in $$\triangle$$ PQR touching the sides QR, PR and PQ at the points S , U and T, respectively. PQ = (QR + 5) cm, PQ = (PR + 2) cm . If the perimeter of $$\triangle$$ PQR is 32 cm ,then PR is equal to:

A

10 cm

B

13 cm

C

8 cm

D

11 cm