Solution
Sum of first $$n$$ natural numbers = $$\frac{n(n+1)}{2}$$
Thus, sum of first 93 natural numbers = $$\frac{93(93+1)}{2}$$
= $$93\times47$$
$$\therefore$$ Average of first 93 natural numbers = $$\frac{93\times47}{93}=47$$
=> Ans - (C)
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