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Question 81
To do a certain work,the ratio of the efficiencies of X and Y is 5 : 4. Working together, they can complete the same work in 10 days. Y alone starts the work and leaves after 5 days. The remaining work will be completed by X alone in:
Solution
Let the efficiency of X and Y be 5p and 4p respectively.
Total work = efficiency $$\times times = (5p +Â 4p) \times 10 = 90p$$
Work done by Y in 5 days = 4p $$\times$$ 5 = 20p
Remaining work =Â Â 90p - 20p = 70p
Time taken by X to complete work = 70P/4p = 14 days
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