The average of 8 consecutive natural numbers is 38.5. What is the largest of these 8 numbers?
Let the 8 consecutive natural numbers be $$(x+1),(x+2),(x+3),....,(x+8)$$
Average of these numbers = 38.5
=>Â $$\frac{(x+1)+(x+2)+(x+3)+....+(x+8)}{8}=38.5$$
=>Â $$8x+36=38.5\times8=308$$
=> $$8x=308-36=272$$
=> $$x=\frac{272}{8}=34$$
$$\therefore$$ Largest number = $$34+8=42$$
=> Ans - (C)
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