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Solution
Expression :Â $$ (7^4)^2 \times \frac{1}{343^2} \times 7 + 17$$
= $$[(7)^8\times\frac{1}{7^6}\times(7)^1]+17$$
= $$[(7)^{8+1-6}]+17$$
= $$343+17=360$$
=> Ans - (C)
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