Question 81

Simplify:
$$ (7^4)^2 \times \frac{1}{343^2} \times 7 + 17 = ?$$

Solution

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Expression : $$ (7^4)^2 \times \frac{1}{343^2} \times 7 + 17$$

= $$[(7)^8\times\frac{1}{7^6}\times(7)^1]+17$$

= $$[(7)^{8+1-6}]+17$$

= $$343+17=360$$

=> Ans - (C)

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