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Let ABCDEF be a regular hexagon with each side of length 1 cm. The area (in sq cm) of a square with AC as one side is
The length of the diagonals of a regular hexagon with side s are $$\sqrt{3}s$$.
Here length of AC =
$$\sqrt{3}s$$ = $$\sqrt{3}$$ cms
Hence area of the square = $$\sqrt{3}^2$$ = 3 sq cm
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