Question 81

In a match, average of runs scored by 7 players is 53. If the runs scored by 6 players are 121, 40, 26, 56, 37 and 48, then how many runs did the 7th player scored?

Solution

Average runs scored by 7 players = 53

=> Total runs scored by the 7 players = $$53\times7=371$$

Total runs scored by the first 6 players = 121 + 40 + 26 + 56 + 37 + 48 = 328

$$\therefore$$ Runs scored by the 7th player = $$371-328=43$$

=> Ans - (C)

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