If $$A, B$$ and $$C$$ are arbitrary events, then $$P(A \cap B \cap C)$$ equals to:

A

$$P(A)P(B \mid A)P(C \mid A \cap B)$$

B

$$P(A)P(A \mid B)P(A \cap B \mid C)$$

C

$$P(A)P(B)P(C)$$

D

$$P(A) + P(B) + P(C)$$