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$$y = \tan^{-1}\left(\frac{x^2}{2}\right)$$ what is $$\frac{dy}{dx}$$?
$$\frac{4x}{(4 + x)}$$
$$\frac{4}{(4 + x^2)}$$
$$\frac{x}{(4 + x^2)}$$
$$\frac{4x}{(4 + x^2)}$$
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