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The maximum value of function $$(xy)^6$$ on the ellipse $$\frac{x^2}{4} + y^2 = 1$$ occur at a point (x, y) for which $$y^2$$ is equal to
$$\frac{\sqrt{2}}{3}$$
$$\frac{1}{2}$$
$$\frac{2}{3}$$
$$\frac{5}{11}$$
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