The maximum value of function $$(xy)^6$$ on the ellipse $$\frac{x^2}{4} + y^2 = 1$$ occur at a point (x, y) for which $$y^2$$ is equal to

A

$$\frac{\sqrt{2}}{3}$$

B

$$\frac{1}{2}$$

C

$$\frac{2}{3}$$

D

$$\frac{5}{11}$$