Question 8
What number should be added to each of 4, 16, 18 and 58 so that the resulting numbers will be in proportion in the given order?
Solution
Let the number added be = $$x$$
Thus, for the new numbers to be in proportion, we have :
=> $$\frac{4+x}{16+x}=\frac{18+x}{58+x}$$
=> $$(4+x)(58+x)=(18+x)(16+x)$$
=> $$x^2+62x+232=x^2+34x+288$$
=> $$62x-34x=288-232$$
=> $$28x=56$$
=> $$x=\frac{56}{28}=2$$
=> Ans - (A)
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