CAT 2022 Question Paper (Slot 2) - Quant Question 8
Question 8
Two ships meet mid-ocean, and then, one ship goes south and the other ship goes west, both travelling at constant speeds. Two hours later, they are 60 km apart. If the speed of one of the ships is 6 km per hour more than the other one, then the speed, in km per hour, of the slower ship is
Solution
Let the speeds of two ships be 'x' and 'x+6' km per hour
Distance covered in 2 hours will be 2x and 2x+12
It is given,
$$\left(2x\right)^2+\left(2x+12\right)^2=60^2$$
$$\left(x\right)^2+\left(x+6\right)^2=30^2$$
$$2x^2+12x+36=900$$
$$x^2+6x+18=450$$
$$x^2+6x-432=0$$
Solving, we get x = 18
The speed of slower ship is 18 kmph
The answer is option C.
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Comments
Shiv Prajapati
11 months, 4 weeks ago
How we have known that this question is related to direction sense while this question is related to time and distance?