For the reaction $$N_2 + 3H_2 \rightarrow 2NH_3$$, the rate expression is $$-\frac{d[NH_3]}{dt} = k[H_2][N_2]$$.
The correct statement is
I. The reaction is not elementary
II. The reaction is of second order
III. $$-\frac{d[H_2]}{dt} = -\frac{d[NH_3]}{dt}$$

A

II only

B

I and II

C

II and III

D

I, II and III