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Question 79
Ramesh had to obtain 36% marks to pass in an examination. He obtained 24% marks and failed by 9 marks. Find the maximum marks of the examination.
Solution
Let the maximum marks in the examination be $$100x$$
Acc. to ques,
=> $$\frac{36}{100} \times 100x = (\frac{24}{100} \times 100x) + 9$$
=> $$36x = 24x + 9$$
=> $$12x = 9$$
=> $$x = \frac{9}{12} = \frac{3}{4}$$
$$\therefore$$ Maximum marks = $$\frac{3}{4} \times 100 = 75$$
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