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The residue of a complex function $$x(z) = \frac{1 - 2z}{z(z - 1)(z - 2)}$$ at its poles are
$$\frac{1}{2}, \frac{1}{2}$$ and $$1$$
$$\frac{1}{2}, \frac{1}{2}$$ and $$-1$
$$\frac{1}{2}, 1$$ and $$-\frac{3}{2}$$
$$\frac{1}{2}, -1$$ and $$\frac{3}{2}$$
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