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Laplace transform of $$f(t) = t^2 \sin t$$ is
$$\frac{3s^2 - 1}{(s^2 + 1)^3}$$
$$\frac{2(3s^2 - 1)}{(s^2 + 1)^3}$$
$$\frac{3s^2 + 1}{(s^2 + 1)^3}$$
$$\frac{2(3s^2 + 1)}{(s^2 + 1)^3}$$
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